0=10+6x-4.9x^2

Solution for 0=10+6x-4.9x^2 equation:

0=10+6x-4.9x^2

We move all terms to the left:

0-(10+6x-4.9x^2)=0

We add all the numbers together, and all the variables

-(10+6x-4.9x^2)=0

We get rid of parentheses

4.9x^2-6x-10=0

a = 4.9; b = -6; c = -10;
Δ = b2-4ac
Δ = -62-4·4.9·(-10)
Δ = 232
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{232}=\sqrt{4*58}=\sqrt{4}*\sqrt{58}=2\sqrt{58}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-2\sqrt{58}}{2*4.9}=\frac{6-2\sqrt{58}}{9.8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+2\sqrt{58}}{2*4.9}=\frac{6+2\sqrt{58}}{9.8}
$